3(x+2)=3[x-(4-x)]

Solution for 3(x+2)=3[x-(4-x)] equation:

Simplifying
3(x + 2) = 3[x + -1(4 + -1x)]

Reorder the terms:
3(2 + x) = 3[x + -1(4 + -1x)]
(2 * 3 + x * 3) = 3[x + -1(4 + -1x)]
(6 + 3x) = 3[x + -1(4 + -1x)]
6 + 3x = 3[x + (4 * -1 + -1x * -1)]
6 + 3x = 3[x + (-4 + 1x)]

Reorder the terms:
6 + 3x = 3[-4 + x + 1x]

Combine like terms: x + 1x = 2x
6 + 3x = 3[-4 + 2x]
6 + 3x = [-4 * 3 + 2x * 3]
6 + 3x = [-12 + 6x]

Solving
6 + 3x = -12 + 6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6x' to each side of the equation.
6 + 3x + -6x = -12 + 6x + -6x

Combine like terms: 3x + -6x = -3x
6 + -3x = -12 + 6x + -6x

Combine like terms: 6x + -6x = 0
6 + -3x = -12 + 0
6 + -3x = -12

Add '-6' to each side of the equation.
6 + -6 + -3x = -12 + -6

Combine like terms: 6 + -6 = 0
0 + -3x = -12 + -6
-3x = -12 + -6

Combine like terms: -12 + -6 = -18
-3x = -18

Divide each side by '-3'.
x = 6

Simplifying
x = 6